How to Represent an Almost Kummer's Equation in Terms of Kummer's or Solve It?

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SUMMARY

The discussion focuses on transforming an almost Kummer's equation into a standard form for easier analysis and solution. The original equation, x*y''+(b-2*x)*y'-a*y=0, is converted using the substitution τ = 2x, leading to the hypergeometric equation τ y''_ττ + (b - τ) y'ₜ - (a/2) y = 0. This transformation simplifies the process of solving the equation by aligning it with known forms. The method is confirmed as effective for representing and solving the equation.

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  • Understanding of differential equations, particularly Kummer's equation.
  • Familiarity with hypergeometric functions and their properties.
  • Knowledge of variable substitution techniques in differential equations.
  • Basic calculus, including differentiation and integration of functions.
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  • Study the properties of Kummer's equation and its solutions.
  • Learn about hypergeometric equations and their applications.
  • Explore variable substitution methods in solving differential equations.
  • Investigate numerical methods for solving differential equations when analytical solutions are complex.
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Mathematicians, physicists, and researchers working with differential equations, particularly those interested in Kummer's equation and hypergeometric functions.

intervoxel
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I met the following equation in my research, which is almost Kummer's equation (without the 2):

x*y''+(b-2*x)*y'-a*y=0

How can I represent this equation in terms of Kummer's? Or else, how solve it?
 
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Take your equation, and make the change of variable

\tau = 2 x

This means that

y^{\prime}_{x} = 2 y^{\prime}_{\tau}

and

y^{\prime \prime}_{xx} = 4 y^{\prime \prime}_{\tau \tau}

Substitute these into your equation, and it becomes

\tau y^{\prime \prime}_{\tau \tau} + (b - \tau) y^{\prime}_{\tau} - \frac{a}{2} y = 0

which is the hypergeomtric equation in the new variable.
 
Perfect! Thank you.
 

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