How to split log(K) = 127.702 to avoid calculator overflow

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r_swayze
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"If your calculator has overflow issues with this problem, you can use this identity to solve for K:

if log(K) = x + y then K = 10x * 10y

Problem:

log(K) = 127.702

K = 5.04316 * 10127 "
Doesn't K = 10127 ?

Where are they getting the 5.04316 from? How are they using that specified identity?
 

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r_swayze said:
"If your calculator has overflow issues with this problem, you can use this identity to solve for K:

if log(K) = x + y then K = 10x * 10y

Problem:

log(K) = 127.702

K = 5.04316 * 10127 "



Doesn't K = 10127 ?

Where are they getting the 5.04316 from? How are they using that specified identity?
If log(K)= 127.702 then K is NOT 10127 because K is NOT 127. You just said "log(K)= x+ y then K= 10x10y. 127.702= 172+ .702 so K= 1012710.702. And 10.702= 5.035006. (but not 5.04315- that would be closer to .703.)