I need some help in this question please check what i have done

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Discussion Overview

The discussion revolves around a homework problem involving the calculation of pH in a buffer solution containing ethanoic acid and sodium ethanoate, as well as the changes in pH upon the addition of HCl and KOH. The scope includes mathematical reasoning and conceptual clarification related to buffer solutions and acid-base reactions.

Discussion Character

  • Homework-related
  • Mathematical reasoning
  • Conceptual clarification

Main Points Raised

  • The initial calculation of pH using the Henderson-Hasselbalch equation was presented, with a resulting pH of 5.046.
  • One participant confirmed the correctness of the first part of the solution.
  • For the second part, a participant suggested assuming that the reaction goes to completion for calculating changes in pH, noting that this approach is not 100% accurate but generally works.
  • There was a question regarding the ratio of [A-]/[HA] in the first part, with one participant suggesting it equals 1.
  • Another participant challenged this assertion by pointing out the explicit amounts of A- and HA given in the problem statement.
  • A participant acknowledged a misunderstanding regarding the totals of all forms after reviewing the problem statement.
  • One participant expressed gratitude after resolving their confusion.

Areas of Agreement / Disagreement

Participants generally agreed on the correctness of the initial pH calculation, but there was disagreement regarding the interpretation of the concentrations of A- and HA in the context of the problem. The discussion remains unresolved regarding the exact approach to calculating changes in pH after the addition of acids and bases.

Contextual Notes

Participants noted that the assumption of complete reaction for calculating pH changes may not be entirely accurate, indicating a limitation in the approach taken.

lioric
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Homework Statement


A 1.00dm3 buffer sollution contains 0.5 mol of ethanoic acid and 1.00 mol sodium ethanoate.

CH3COOH: Ka= 1.8x10-5

Calculate pH of solution
Calculate change in pH when 1cm3 of 1M HCl is added
Calculate change in pH when 2cm3 of 1.5M KOH is added

Homework Equations



pH=pKa + log [A-/HA]


The Attempt at a Solution



pH=pKa + log [A-/HA]

So pH= 4.7 + log [1/0.5] (I changed Ka to pKa)

pH=5.046

Is that ok?


The next part is confusing


A- + HCl → HA + Cl-

Initial conc.
A-= 1M
HCl =(What do i write for HCl conc)
HA= 0.5
 
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1st part is OK.

For the second and third simply assume reaction (A- protonation or HA neutralization) went to completion and concentrations can be calculated from a simple stoichiometry. This is not 100% accurate, but works in most cases.
 
For first part doesn't [A-]/[HA] = 1?
 
Why? Questions states explicitly 1 mole of A- and 0.5 mole of HA.
 
Borek said:
Why? Questions states explicitly 1 mole of A- and 0.5 mole of HA.

Ah yes I had hastily read it for totals of all forms. :blushing:
 
thank you very much i figured it out
 

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