Ideal Transformer: Solve for Turn Ratio, kVA Rating, Primary Current

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SUMMARY

The discussion focuses on calculating the turn ratio, kVA rating, and primary current for an ideal transformer with a rated voltage of 11000/4600 V and a secondary current of 30 A. The turn ratio is determined to be 0.418 using the formula N=V2/V1. The kVA rating is calculated as 138 kVA using the equation S=VI, specifically S2=4600*30. The primary current is found to be 12.5 A, derived from the relationship I1=(4600*30)/(11000).

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Homework Statement


Ideal Transformer:
rated: 11000/4600 V
secondary current: 30A

Find turn ratio, kVA rating, primary current

Homework Equations


S=VI
N=V2/V1

The Attempt at a Solution


Are these correct?
Turn ratio: N=V2/V1 = 0.418
kVA = S1*I1 = S2*I2 = 4600*30 = 138kVA
Primary current: V1*I2 = V2*I2=>I1=(4600*30)/(11000) = 12.5A
 
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eehelp150 said:
Are these correct?
Turn ratio: N=V2/V1 = 0.418
kVA = S1*I1 = S2*I2 = 4600*30 = 138kVA
Primary current: V1*I2 = V2*I2=>I1=(4600*30)/(11000) = 12.5A
Yes.
 

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