Identify the oxidizing agent and reducing agent

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SUMMARY

The chemical reaction Sn(s) + NO3- → SnO2(s) + NO(g) involves tin (Sn) acting as the reducing agent and nitrogen (N) in nitrate (NO3-) as the oxidizing agent. In this reaction, tin loses four electrons, confirming its role as the reducing agent, while nitrogen gains three electrons, establishing it as the oxidizing agent. Oxygen remains unchanged with a -2 oxidation state and does not participate in the electron transfer process.

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Homework Statement


Sn(s)+NO3--->SnO2(s)+NO(g)

Homework Equations


The Attempt at a Solution


0 |+5 ,-2| |+4,-2| |+2,-2|
Sn(s)+NO3--->SnO2(s)+NO(g)
Sn lost 4e reducing agent
N gain 3e oxidizing agent
is that right?
What about oxygen?? do i do the same thing?
thanks
 
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The Oxygen is neither gained nor lost electrons. It stays by -2.
and yes I thibk you`re right.
 

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