Identifying Cyclic Alkanes: C6H12 - C9H18 - C10H20

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This discussion focuses on the correct naming of cyclic alkanes with formulas C6H12, C9H18, and C10H20. The first compound, 1-ethylcyclobutane, was initially misnamed but correctly identified as ethylcyclobutane. The second compound, 1-methyl-3-propylcyclopentane, was confirmed as correct. The third compound was clarified to be 2-ethyl-1,3-dimethylcyclohexane, emphasizing the importance of numbering substituents to achieve the lowest possible numbers.

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Homework Statement


Name each of the following cyclic alkanes, and indicate the formula of the compound.
http://img230.imageshack.us/img230/1042/organicnaming.jpg


Homework Equations





The Attempt at a Solution


a. The rectangle has four corners so four carbon for butane. The branch off has two carbons so eth-. Numbering the branch C as 1, the naming is 1-ethylcyclobutane with C6H12 because each corner is 1 C plus the C written and the H comes from subtracting 4 with the number of bonds connected to each of the C. Is this correct?

b. The pentagon has five corners so five corner for pentane. The branch off is prop- and meth-. Naming starts with alphabetical order so meth- first so the prop- is three. 1-methyl-3-propylcyclopentane. Logic from a., C9H18. Is this correct?

c. Hexane from six corners. Dimethyl and ethyl here. Is this named 1-ethyl-2,6-dimethylcyclohexane or 2-ethyl-1,3-dimethylcyclohexane? C10H20.

If there is a mistake, which part?
 
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312213 said:

Homework Statement


Name each of the following cyclic alkanes, and indicate the formula of the compound.
http://img230.imageshack.us/img230/1042/organicnaming.jpg


Homework Equations





The Attempt at a Solution


a. The rectangle has four corners so four carbon for butane. The branch off has two carbons so eth-. Numbering the branch C as 1, the naming is 1-ethylcyclobutane with C6H12 because each corner is 1 C plus the C written and the H comes from subtracting 4 with the number of bonds connected to each of the C. Is this correct?

b. The pentagon has five corners so five corner for pentane. The branch off is prop- and meth-. Naming starts with alphabetical order so meth- first so the prop- is three. 1-methyl-3-propylcyclopentane. Logic from a., C9H18. Is this correct?

c. Hexane from six corners. Dimethyl and ethyl here. Is this named 1-ethyl-2,6-dimethylcyclohexane or 2-ethyl-1,3-dimethylcyclohexane? C10H20.

If there is a mistake, which part?

A is just ethylcyclobutane. There is no need to number the substituent, since a cycloalkane with 1 substituent will always have it at the #1 carbon. You had the formula right.

B is correct.

C is 2-ethyl-1,3-dimethylcyclohexane (you number so as to give your substituents the lowest number possible, in the absence of priority substituents such as OH). Formula is correct.
 
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