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Identity of metal from electrolysis

  1. Jul 2, 2016 #1

    TT0

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    1. The problem statement, all variables and given/known data
    A solution of a trivalent metal ion is electrolysed by a current of 5.0A for 10 minutes during which time 1.18g of metal was plated out. The identity of the metal is:

    A cobalt
    B chromium
    C indium
    D gallium
    E bismuth

    Relative atomic masses:
    1 faraday = 96,486 coulombs.

    2. Relevant equations
    current*time=coulombs
    coulombs/96486=faraday
    1 faraday = 1 mol of electrons

    3. The attempt at a solution
    5.0*10*60=3000 coulombs
    3000/96486=0.031092 mol of electron

    Since trivalent metal ion, mol of metal = 0.031092/3 = 0.010364 mols

    Trial and error by dividing 1.18 by molar mass shows indium is closest. 1.18/114.82 = 0.1028. Is this the correct answer?

    Cheers!
     
  2. jcsd
  3. Jul 2, 2016 #2

    Borek

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    Staff: Mentor

    Yes, indium sounds good.
     
  4. Jul 2, 2016 #3

    TT0

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    Thanks!
     
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