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**1. use implicit differentiation to evaluate y(prime) for x^3+y^3=4xy+1 at the point (2,1)**

- Thread starter the_ace
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- #2

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An attempt please?

- #3

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(Y=y prime)

3x^2+3y^2Y=4y+4Y

- #4

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Yes you are right. Now, solve for Y and sub in the coordinates.

- #5

HallsofIvy

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The derivative of y with respect to x is more commonly wriitten as y', not "Y".

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