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Implicit differentiation on x^3 + y^3 = 4xy + 1

  1. Oct 8, 2009 #1

    the_ace

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    1. use implicit differentiation to evaluate y(prime) for x^3+y^3=4xy+1 at the point (2,1)
     
    the_ace, Oct 8, 2009
  2. jcsd
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  3. Oct 8, 2009 #2

    physicsnoob93

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    Re: differentiation

    An attempt please?
     
    physicsnoob93, Oct 8, 2009
  4. Oct 8, 2009 #3

    the_ace

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    Re: differentiation

    (Y=y prime)
    3x^2+3y^2Y=4y+4Y
     
    the_ace, Oct 8, 2009
  5. Oct 8, 2009 #4

    physicsnoob93

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    Re: differentiation

    Yes you are right. Now, solve for Y and sub in the coordinates.
     
    physicsnoob93, Oct 8, 2009
  6. Oct 8, 2009 #5

    HallsofIvy

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    Re: differentiation

    The derivative of y with respect to x is more commonly wriitten as y', not "Y".
     
    HallsofIvy, Oct 8, 2009
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