- #1

chwala

Gold Member

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- Homework Statement
- see attached

- Relevant Equations
- differentiation

##6x^2+6y+6x\dfrac{dy}{dx}-6y\dfrac{dy}{dx}=0##

##\dfrac{dy}{dx}=\dfrac{-6x^2-6y}{6x-6y}##

##\dfrac{dy}{dx}=\dfrac{-x^2-y}{x-y}##

Now considering the line ##y=x##, for the curve to be parallel to this line then it means that their gradients are the same at the point##(1,1)##

##\dfrac{dy}{dx} (x=1)=\dfrac{-1-1}{1-1}=\dfrac{-2}{0}## does not exist...

i hope this is the correct approach unless i am missing something.

* I do not have the solution.