picture a body falling toward a black hole.(adsbygoogle = window.adsbygoogle || []).push({});

at the center of the black hole you have an infinite amount of force pulling you toward the center: F=Gm1m2/x^2 while x=0. F=infinity

so at a certain distance away from the black hole you have a certain force pulling you in.

but as you approach the center your acceleration increases.

but as you accelerate your velocity increases

so you were once not moving at you initial position. after a few seconds you start moving due to the force pulling you in.

but what happens is you gain velocity so now your acceleration is increasing.

but since you are accelerating your velocity starts to jerk.

the jerk effects the acceleration and you get a cycle of one derivative influencing the next.

so the position vs time graph becomes infinitely differentiable.

if you look at it in terms of energy:

work=force x distance

so Kinetic energy would be the integral of f=Gm1m2/x^2

your velocity is the square root of 2 times the integral

if change in momentum=impulse

m x dv= f x t

we have m2 x our velocity = f x t

we have force for a given X but not a given T so we cannot integrate Gm1m2/x^2

so to be able to graph x vs t we need f vs t

please help if you have any insight

**Physics Forums - The Fusion of Science and Community**

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Impossible to graph position vs time?

Loading...

Similar Threads - Impossible graph position | Date |
---|---|

Synchronization of time impossible? | Dec 17, 2013 |

How to read this orbital graph? | Sep 2, 2013 |

Alt vs local Time graph. | Mar 23, 2013 |

Graphs of galaxy rotation curves? | Feb 15, 2010 |

A hypothetical and impossible solution to the origin of the Universe. | Sep 25, 2009 |

**Physics Forums - The Fusion of Science and Community**