Integrating Momentum Space: Replacing hslash with d

[the1ceman]

does anyone knw the code for how to produce the d slash notation in the integration measure for momentum space? Where (d slash)^n X=(d^n)X/((2pi)^n).
Basically all i want to do is replace the h:
$$\hslash$$
with a d.

 

[tiny-tim]

not!

Hi the1ceman!

does anyone knw the code for how to produce the d slash notation in the integration measure for momentum space? Where (d slash)^n X=(d^n)X/((2pi)^n).
Basically all i want to do is replace the h:
$$\hslash$$
with a d.

hmm … interesting …

i did a google search, and found this …

Here's a crude make-shift attempt for whatever it's worth. I just did this by goofing around.

I have no idea how to do it formally, of if there even is a formal way to do it.

$$\displaystyle{\not} \partial = \gamma_i \partial^i$$

$$\displaystyle{\not} p = \gamma_i p^i$$

$$\displaystyle{\not}A = \gamma _i A^i$$

He did it by typing \displaystyle{\not} …

but you can also do it with just {\not} …

(presumably because LaTeX regards a letter with a slash through it as "not" that letter )

$${\not} \partial = \gamma_i \partial^i$$
$${\not} p = \gamma_i p^i$$
$${\not}A = \gamma _i A^i$$

 

[the1ceman]

thanks for the reply tim but I am not after the feynman slash notation! Basically in the latex command \hslash i just want to replace the 'h' by a 'd', so that the top end of the 'd' has a diagonal line through it, not the whole letter (as in the feynman slash notation).
Im almost there, basically i have to create a macro, but i need to find the code for the 'slash' in \hslash.

 

[robphy]

Try this
$$\newcommand{\dslash}{d \hspace{-0.8ex}\rule[1.2ex]{0.8ex}{.1ex}}<br /> \dslash \hbar$$
(using a horizontal bar).

 

[tiny-tim]

negative space!

Try this
$$\newcommand{\dslash}{d \hspace{-0.8ex}\rule[1.2ex]{0.8ex}{.1ex}}<br /> \dslash \hbar$$
(using a horizontal bar).

oh, robphy, that's great! …

you've invented negative space!
​

you've inserted a negative space "after" the d (using \hspace{-0.8ex}), and put a horizontal bar in it.

(btw, you can leave out "\newcommand" at the start, and "\dslash " at the end: $${d \hspace{-0.8ex}\rule[1.2ex]{0.8ex}{.1ex}}$$ )

Does CERN know about this? ​

 

[the1ceman]

Try this
$$\newcommand{\dslash}{d \hspace{-0.8ex}\rule[1.2ex]{0.8ex}{.1ex}}<br /> \dslash \hbar$$
(using a horizontal bar).

thanks for the reply, i have actually done this already, but with a different command, is it possible to get the 'slash' slightly horizontal? Sorry for being so pedantic!