- #1
AxiomOfChoice
- 533
- 1
I know the eigenvalues of a Hermitean operator are necessarily real, and we want energies to be real...but isn't it possible for non-Hermitean operators to have real eigenvalues? If that's so, shouldn't it be possible for at least some Hamiltonians to be non-Hermitean?
Also, is it possible for any real differential operator of the form
[tex]
- \frac{\hbar^2}{2m} \Delta + V
[/tex]
to be non-Hermitean?
Also, is it possible for any real differential operator of the form
[tex]
- \frac{\hbar^2}{2m} \Delta + V
[/tex]
to be non-Hermitean?