Is it possible hf=kT? Conditions Explained

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The equation hf = kT relates the energy of a photon to thermal energy at a given temperature. This equality holds true for any frequency f, as there exists a corresponding temperature T that satisfies the equation. It is commonly applied in contexts involving thermal radiation and transitions between classical and quantum regimes. The discussion highlights that this relationship is frequently utilized, though it may not always be explicitly computed. Understanding the conditions under which hf equals kT is essential for analyzing thermal processes in physics.
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is it possible hf=kT? Under what condtion, it will be the same? where h is Plack constant, f is frequency and k is Boltzmann constant, T is temperature
 
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For any frequency f, there is a T which satisfies the equation.
 
...edit:wait jtbell is this ever computed? I have never seen such an equality
 
Last edited:
HomogenousCow said:
...


edit:wait jtbell is this ever computed? I have never seen such an equality

It is used all the time. Any relation which involves thermal radation to/from a body held at a temperature T will involve thesee terms.
At hf=kBT there are often "transitions" of some sort. In some cases you have a transition from the classical (thermal) to quantum regime when hf=kBT
 

Thread 'Two equivalent statements of time reversal symmetric Hamiltonian'

Time reversal invariant Hamiltonians must satisfy ##[H,\Theta]=0## where ##\Theta## is time reversal operator. However, in some texts (for example see Many-body Quantum Theory in Condensed Matter Physics an introduction, HENRIK BRUUS and KARSTEN FLENSBERG, Corrected version: 14 January 2016, section 7.1.4) the time reversal invariant condition is introduced as ##H=H^*##. How these two conditions are identical?
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