Is there any reason i is left in the denominator here?

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The discussion centers on the presence of the imaginary unit 'i' in the denominator of equations related to continuity equations and probability current in quantum mechanics (QM). Users noted that while it may seem unconventional or "bad voodoo" to leave 'i' in the denominator, this practice is standard in physics literature. The consensus is that this convention is widely accepted among professionals and does not affect the functional outcome of the equations. The discussion highlights the difference between student perceptions and professional standards in mathematical representation.

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Zacarias Nason
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I'm reading up on continuity equations and in particular how it relates to the probability current, and I noticed both in the Wikipedia page subsection for QM talking about continuity equations and in the main page for probability current, plenty of the formulas given have i in the denominator of the coefficient at the front; is there any reason the eqns are left this way rather than multiplying both sides by i^2 and then multiplying through by -1 so the LHS is still the same sign but i isn't in the denominator? Leaving the i as is is just sort of "bad voodoo" to me but functionally the same and I'm curious if there's any convention or if that's just some bias I've developed on my own.
 
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It's one of those things students develop from drills but it is not followed by professionals. Imaginary i in the denominator is common in physics literature. Same goes for radicals / square roots.
 
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