Is there anything else you'd like to check?

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Topher925
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I feel like an idiot asking this, but I need a check on a derivation. Can anyone verify this for me or let me know if its wrong?

Homework Statement



Expand the equation.

Homework Equations



0 = m[tex]\frac{d}{dr}[/tex]([tex]\frac{1}{r}[/tex][tex]\frac{d}{dr}[/tex](ru))

The Attempt at a Solution



[tex]\frac{d2u}{dr2}[/tex]+[tex]\frac{1}{r}[/tex][tex]\frac{du}{dr}[/tex]-[tex]\frac{u}{r2}[/tex] = 0

or

u'' + u'/r - u/r2 = 0
 
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Topher925 said:
Expand the equation.

0 = m[tex]\frac{d}{dr}[/tex]([tex]\frac{1}{r}[/tex][tex]\frac{d}{dr}[/tex](ru))

u'' + u'/r - u/r2 = 0

Hi Topher925! :wink:

Yes, that's fine. :smile:
 
tiny-tim said:
Hi Topher925! :wink:

Yes, that's fine. :smile:

Crap. I was afraid someone was going to say that.