- #1

- 82

- 0

## Main Question or Discussion Point

So say you have an object of mass "m" on a water wave that happens to be a perfect sine wave. Just to reassure you this is NOT a homework question. So here's my idea so tell me if its correct. We know that Fg = m x g x delta"h". We know that the hight traveled by the object on the wave is going to be 2 x the amplitude of the wave. So can i say that the force felt by the object will be the mass of the object x g x (2 x the amplitude)? I mean not the force at a specific point because the object on the wave is not in free fall but the overall difference of potential energy and therefore energy should be the same as it would be if the object were in free fall but it is felt over a longer period of time. So with this said i thought well the maximum force is at the peak or troph of the wave and seeing as in a sine wave there is one peak and one troph per cycle the calculation for the amount of times the peak and troph is passed should be (0.5 x lambda)/v so therefore if the object was on the wave for 3600s, we could calculate how many times a peak or troph was passed. So to sum up my idea i say that if the mass of the object on the wave was 5kg, lambda was 10s, v was 2m/s, the amplitude of the wave was 1.5m, and the object was on the wave for 3600s, I would wright the equation as (5 x 9.81 x 2(1.5)) x 3600) divided by ((0.5 x 10)/2) and find that the total energy that the mass felt was 21186N. I see room for a few problems here but i wanted your opinion before i started from scratch again.