I've found this site that states: "The surface gravity on Mars is only about 38% of the surface gravity on Earth." So a 100 lbs object will weigh about 38 lbs or a 45.359 kg will be on Mars 17.237 kg (converting 38 lbs in kg). So to find the F(adsbygoogle = window.adsbygoogle || []).push({}); _{g}of Mars, I did this kind of equation:

[tex]

\frac{45.359 kg}{444.518 N} = \frac{17.237 kg}{X}

[/tex]

(444.518)(17.237) = (45.359)(X)

7662.156766 = 45.359X

[tex]

\frac{7662.156766}{45.359} = X

[/tex]

168.9225 N = X

-----------------------------------

Now that we know the weight of the object in newtons on Mars' surface, then:

17.237 kg ÷ X = 168.9225 N

X = 0.10204876 N

F_{gravity}= 0.10204876 N

So the force of gravity on Mars surface is approximately 0.10204876 Newtons, right? The site that I found the information at is: [URL]http://coolcosmos.ipac.caltech.edu/cosmic_kids/AskKids/mars_gravity.shtml[/ur].

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# Is this the approximate gravity of Mars?

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