Limit x→0+ x^(1/x - 1): Is It Defined?

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SUMMARY

The limit as x approaches 0 from the positive side of the expression x^(1/x - 1) is definitively calculated to be 0. The calculation involves transforming the limit into an exponential form using natural logarithms, leading to the conclusion that e raised to the power of negative infinity equals 0. However, a discrepancy arises when using the WIMS calculator, which indicates that the limit is not defined. This highlights the importance of understanding the behavior of logarithmic functions near zero.

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  • Knowledge of L'Hôpital's Rule for indeterminate forms
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Homework Statement


I was doing a problem and got to the following limit:
[tex]lim_{x \rightarrow 0^{+}} x^{\frac{1}{x} - 1}[/tex] I calculated it and got 0 but when I calculated it here:
http://wims.unice.fr/wims/en_tool~analysis~function.en.html
It said that it wans't defined. Am I right?
Thanks.

Homework Equations


The Attempt at a Solution

 
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try the following:
[tex]lim_{x \rightarrow 0^{+}} x^{\frac{1}{x} - 1}=\lim_{x\rightarrow 0^{+}}e^{ln(x)^{\frac{1}{x}-1}}=\lim_{x\rightarrow\ 0^{+}} e^{\frac{1-x}{x}ln(x)}=e^{\lim_{x\rightarrow\ 0^{+}}\frac{1-x}{x} \lim_{x\rightarrow\ 0^{+}}ln(x)}=e^{\infty*(-\infty)}=e^{-\infty}=0[/tex]
 
Thanks, that's what I did but the wims calculator confused me.
 

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