Limiting Reagent Qs: NaOH & H2SO4 | C6H6 & Br2

[hockeyfghts5]

Homework Statement

Question 1
How would your solve this? I balanced it now i am stuck. Same with the second problem.
2 NaOH + H2SO4 = Na2SO4 + 2 H2O

If 14.56 g of NaOH was reacted with 13.49 g of H2SO4, how many grams of water would be produced. (Hint What is the limiting reagent?)

Question 2

C6H6 + Br2 = C6H5Br + HBr

Benzene and bromine react to form bromobenzene, as represented by the equation below. If 8.02 g of benzene were reacted with 14.93 g of bromine, how many grams of the non-limiting reagent is unreacted

Homework Equations

The Attempt at a Solution

 

[symbolipoint]

You correctly balanced the reaction for reactants and products. The reaction uses 2 moles of NaOH for 1 mole of H2SO4. Decide how this ratio compares to the ratio of your given grams of each which are used in the example.

 

[hockeyfghts5]

do i take the ratio of of each of the given grams?

 

[Borek]

Think in terms of moles, not masses.

 

[DarylMBCP]

I believe that what Borek is saying is that the number/coefficient infront of each compound in your balanced equation is to indicate the ratio of moles/particles of each compound. After understanding this, you can try to find the number of moles of NaOH using its mass as given in your question and use the ratio to find the number of moles of H2SO4. Then you can find the number of moles of H2SO4 with its mass as stated in the question and compare the amounts. This should help with finding the limiting reactant.