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1) for2 distinct roots,the solution should be y = Ae^m1x + Be^m2x

2) forReal and equal rootsshould be

y = e^mx(A + Bx) that is it.

So if same roots as the 2nd one,one solution is y1(x)=Ae^mx, what about the second solution?

there is a second solution given by y2(x)=Be^mxx

HERE IS THE PROBLEM!!! WHY THERE EXISTED ANTHERE????!!!x

is this should be y2(x)=Be^mx also? because looks same as distinct root solution, and we can just put the 2 roots in the same just act like there have 2 distinct roots but are the same.

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# Looks same as distinct root solution

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