Mastering Coordinate Planes: Finding the Closest Plane to a Sphere's Center

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    Coordinate Planes
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SUMMARY

The discussion focuses on determining which of the three coordinate planes (XY, YZ, XZ) is closest to the center of a sphere defined by the equation (x-7)²+(y-7)²+(z-7)²=36. The center of the sphere is located at the coordinates (7, 7, 7). To find the closest plane, one must calculate the perpendicular distances from the center to each plane, concluding that the distances to the XY, YZ, and XZ planes are equal, thus indicating that the sphere is equidistant from all three planes.

PREREQUISITES
  • Understanding of 3D coordinate geometry
  • Familiarity with the equation of a sphere
  • Knowledge of distance formulas in three dimensions
  • Basic concepts of coordinate planes (XY, YZ, XZ)
NEXT STEPS
  • Study the properties of spheres in 3D geometry
  • Learn how to calculate distances from points to planes
  • Explore the concept of coordinate transformations
  • Investigate applications of coordinate planes in physics and engineering
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Students studying geometry, educators teaching coordinate systems, and anyone interested in spatial analysis in mathematics or physics.

hungrymouth
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1. Determine which of the three coordinate planes is closest to the center of the sphere(or indicate which planes are tied if two or more of the distances are the same)
(s-7)^2+(y-7)^2+(z-7)^2=36




Homework Equations





3. Would i just try setting x,y,z in turns equal to 0 to find out? That's what I'm thinking but I'm not sure...
 
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Hint: What are the coordinates of the center of the sphere?
 
First determine the center of the sphere then look at its coordinate and ask yourself to which plane is it closest to?

If I have a point in 2D of (3,1) is it closer to the x-axis or the y-axis?
 

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