Max Photo Current Calculation Using Platinum's Work Function

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SUMMARY

The maximal photo current (Io) achievable with platinum's work function of 6.35 eV and an irradiation power of 1.27 W can be calculated using the relationship between power, voltage, and current. The equation hf = wo indicates that the energy of the photons must equal the work function to release electrons. The current is directly related to the number of electrons freed per second, which is determined by the available energy from the power input.

PREREQUISITES
  • Understanding of photoelectric effect principles
  • Familiarity with the work function concept in materials science
  • Basic knowledge of electrical power equations (P=VI)
  • Experience with energy calculations in physics
NEXT STEPS
  • Calculate the maximal photo current using the formula Io = P/hf
  • Explore the implications of varying the work function on photo current
  • Investigate the effects of different irradiation powers on electron emission
  • Learn about the photoelectric effect in various materials beyond platinum
USEFUL FOR

Physics students, electrical engineers, and researchers in materials science focusing on the photoelectric effect and its applications in photovoltaic technologies.

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1. Platinum has a very high work function of wo = 6.35 eV.What is the maximal photo current Io that can be achieved with an irradiation power of
P = 1.27 W ?




Homework Equations


hf = wo


The Attempt at a Solution


Well, Since the only information they give here is the work function, then i assume that it is related to the voltage. I'm trying to use P=VI to find I but it's the voltage part that's confusing me.
 
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The current is charge per unit time so it will depend on how many electrons can you break free in one second.
For each one you need the energy wo.
The given power tells you how much energy is available per second...
 

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