Maximizing Revenue for Lakeside Amusement Park

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SUMMARY

The discussion centers on maximizing revenue for Lakeside Amusement Park by analyzing the relationship between ticket price and customer attendance. The revenue function is defined as D(n) = (25.00 + 1.00n)(20,000 - 750n), where n represents the number of $1.00 increases in ticket price. To find the maximum revenue, participants suggest methods such as graphing the function, using calculus, or applying the vertex formula for quadratic equations. The consensus is that the maximum revenue occurs at a specific ticket price, which can be determined through these methods.

PREREQUISITES
  • Understanding of quadratic functions and their properties
  • Basic knowledge of revenue calculations in economics
  • Familiarity with graphing techniques
  • Introduction to calculus concepts (optional for advanced methods)
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  • Learn how to derive maximum values using the vertex formula for quadratic equations
  • Explore graphing techniques for visualizing revenue functions
  • Study basic calculus principles relevant to optimization problems
  • Investigate the impact of price elasticity on customer attendance
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Economists, business analysts, and students studying revenue optimization strategies in the context of pricing and customer behavior.

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Homework Statement


An average of 20 000 people visit the Lakeside Amusement Park each day in the summer. The admission fee is $25.00. Consultants predict that, for each $1.00 increase in the admission fee, the park will lose an average of 750 customers a day. Determine the function that represents the projected daily revenue if the admission fee is increased AND estimate the ticket price that will maximize function.


Homework Equations


I figured out the equation of the revenue, which I'm sure is correct. It is:

D(n) = (25.00 + 1.00n)(20 000-750n)

let n represent the number of times the price increases.



The Attempt at a Solution


However, I did not understand the second question, do you have to lower the ticket price to maximize revenue? Also, can anyone explain an fast way to determine a maximum revenue, because my method involves choosing random numbers and plopping them into the equation until I find a good value?

Thanks everyone! :)
 
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There are two ways to do this: one involves calculus, so I won't cover that, and the other involves the graph.

Just take a look at the graph and ask yourself, when does the graph appear to max out?

Also, a little personal tip: in a quadratic equation, the maximum is usually halfway between the two zeroes, at least in my experience.

Sorry if I spoke too much.
 
Congrats, you have the right revenue function, just expand it so it is quadratic. There are three methods:

1. Calculus: This is the easiest method(this question seems to be a preview of differential calculus).

2. Graph it.

3. Plug in different numbers and "zoom-in" into the maximum.

4. Your teacher may have told you the formula for finding the maximum of a quadratic function, I remember our Algebra II teacher gave us the formula.
 
I'm not learning Calc until next semester, but I just graphed it and plugged in some values.
Thanks guys!
 

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