MHD Generator Performance with Ionised Gas

[T C]

TL;DR

I want to that instead of plasma, if just ionised gas is used in an MHD Generator, will it work in the same way.

As per this wikipedia page, plasma is necessary for functioning of an MHD Generator. But, what I want to know is if just simple ionised gas is used instead of plasma, will the generator perform in the same way?
As per my little knowledge of physics, there is no reason that it wouldn't. Because whether plasma or ionised gas, both will perform in the same manner while passing through a magnetic field.

 

[Vanadium 50]

What distinction are you drawing between "plasma" and "ionized gas"?

 

[T C]

Plasma is when gas is divided into electron and ion (sometimes just the nucleus) while ionised gas means gas molecules are ionised. In short, for plasma the grand total charge is zero as the number of free electrons and positively charges ions are same. While for ionised gas it's either positive or negative.
But, as per my little knowledge of physics, the effect can't be different.

 

[T C]

My common sense tells me that there should be no difference, but to be assured I have posted this site. But as there is no reply, then I can conclude that it can be possible. At least there is no theoretical opposition to it.

 

[Tom.G]

https://www.researchgate.net/post/what_is_the_difference_between_plasma_and_gas_discharge

 

[T C]

I have clearly said what I want to mean by Plasma. Whatsoever, as per the link, the behaviour of plasma and ionised gas isn't much different while being used in MHD generators. That's my conclusion.

 

[anorlunda]

Whatsoever, as per the link, the behaviour of plasma and ionised gas isn't much different while being used in MHD generators. That's my conclusion.

An ionized gas with nonzero net charge will have repulsive forces between the like charged particles. Are you concluding that those forces are negligible in MHD?

 

[Rive]

But, what I want to know is if just simple ionised gas is used instead of plasma, will the generator perform in the same way?

It definitely won't perform 'the same way', but it'll still work. It will work with any mass what contains charged particles.
Salted water included.

 

[T C]

That's the kind of answer that I want to hear so far.