Minkowski vacuum: Poincare invariant, quasi-free state

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SUMMARY

The Minkowski vacuum is definitively characterized as both Poincare invariant and a quasi-free state. The discussion raises the question of whether these two conditions fully define the Minkowski vacuum or if additional states exist that meet these criteria. It is established that in advanced Quantum Field Theory (QFT), the vacuum is defined as the lowest-energy eigenstate of the full interacting Hamiltonian, which may differ from the lowest-energy eigenstate of the free Hamiltonian. The conditions specified involve the invariance of the two-point function under the Poincare group and the expressibility of all n-point functions in terms of the two-point function.

PREREQUISITES
  • Understanding of Quantum Field Theory (QFT)
  • Familiarity with Poincare group representations
  • Knowledge of Hamiltonian mechanics in quantum systems
  • Concept of quasi-free states in quantum physics
NEXT STEPS
  • Study Weinberg's "Quantum Theory of Fields, Volume 1" for insights on interacting representations of the Poincare group
  • Explore the mathematical formulation of two-point functions in QFT
  • Research the implications of quasi-free states on quantum correlations
  • Investigate the differences between free and interacting Hamiltonians in QFT
USEFUL FOR

This discussion is beneficial for theoretical physicists, quantum field theorists, and advanced students in physics who are exploring the properties of the Minkowski vacuum and its implications in quantum mechanics.

paweld
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Minkowski vacuum is Poincare invariant and quasi-free state.
I wonder if these two conditions fully define it or there are more
states which fulfill these conditions (or maybe Poincare
invariance alone is sufficinet). Thanks for answers.
 
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paweld said:
Minkowski vacuum is Poincare invariant and quasi-free state.
I wonder if these two conditions fully define it or there are more
states which fulfill these conditions (or maybe Poincare
invariance alone is sufficient).

I'm not entirely sure what you're asking. In advanced QFT, one attempts to
construct something called an "interacting representation" of the Poincare
group. (See Weinberg vol 1). The vacuum is still defined as the lowest-energy
eigenstate of the (full, interacting) Hamiltonian -- which often does not coincide
with the lowest-energy eigenstate of the free Hamiltonian.
 
My question is whether a state which fulfills two condition:
(1) its two point function is invariant under action of Poincare
group and
(2) all n-point function can be express in terms of two point function by
the sum over all parings (quasi-free state)
has to be Minkowski vacuum.
 

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