Mistake when explaining associativity of vector addition

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SUMMARY

The discussion clarifies the concept of associativity in vector addition, specifically addressing a potential mistake in visualizing the operation at 6:18. The participants confirm that vector addition is associative, meaning that the order of addition does not affect the result. They emphasize that regardless of whether one adds vectors as a + (b + c) or (b + c) + a, the outcome remains consistent. The notation simplification is also discussed, highlighting that the starting points of vectors can be omitted for clarity without altering the mathematical validity.

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CynicusRex
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Does he make a mistake at 6:18?

In case of associativity. When doing a+(b+c) he's just placing the tip of a to the tail of (b+c), but shouldn't he have added the tail of a to the tip of (b+c) ending in a different point? I understand vector addition is associative, but I think how he did it is incorrect by accident. As far as I understand, this is how I see it:
bkV2hu8.jpg
 
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He is right. He calculates ##a + (b+c)##, i.e. ##(b+c) = v## first and then ##a + v##. Your suggestion is ##v + a##.
To add vectors, you have to apply them at the same point (and get a diagonal of a parallelogram) or concatenate them (and get the same diagonal). So even ##v + a## will lead to the same result, when applied to the origin.

The whole vector addition is already an abbreviation, since a vector should be ##(P_v,v)## where ##P_v## is the point the vector is applied to, i.e. where it starts. So
$$a + (b+c) = (P_a,a) + ((P_b,b) + (P_c, c)) = (P_a,a) + ((P_b,b) + (P_b +b, c)) = (P_a,a) + (P_b, b+c)) = (P_a, a+(b+c))$$
which is associative and commutative. So no matter how you write it, it's always the same result. Since parallel transport along straight lines doesn't change the resulting vectors, we drop the points where the vectors apply to in the notation for simplification.
 
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Ah okay, I understand my error. Thank you.
 

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