1. The problem statement, all variables and given/known data How many degrees(Celsius) would the temperature rise if 4,0g of NaOH was initially dissolved in 50mL of water. 2. Relevant equations Calculate the molar enthalpy change of solution based on this information: - 4g NaOH(s) gets dissolved in 250mL of water, and the temperature rose from 19,5 to 23.0 Celsius. - 4.18 J to raise temperature in 1 gram of water 1 Celsius. - Water density: 1,0g/mL. - No energy was exchanged with the surroundings before the temperature change was measured. I solved this and ended up with 36,575 kJ/mol 3. The attempt at a solution Here is what I`ve tried: 50ml of water = 50 grams Molar mass of water: 18,016 g/mol 50/18,016= 2,7753 mol 2,7753 mol * 36,575 kJ/mol= 101kJ 101kJ * 1000= 101000 J 101000/4,18 J/g * Celsius=24162 24162/1000=24,16 Celsius ??? 19,5+24,16= 43 Celsius?? I dont understand? The correct answer is from 19,5 to 37.0 Celsius.