cjc0117
- 91
- 1
grey=carbon; white=hydrogen; blue=nitrogen
After assigning priorities, I concluded that the carbon attached directly to the nitrogen is an S enantiomer and the carbon attached directly to that carbon (the one not in a ring) is an R enantiomer.
I decided to treat the benzene rings as substituents (phenyl groups). Thus, the longest carbon skeleton has three carbons. The carbon attached to the nitrogen is the number 1 carbon.
I came up with the following name:
(1S,2R)-1,2-diphenyl-1-propanamine
Would you agree? Thanks.
After assigning priorities, I concluded that the carbon attached directly to the nitrogen is an S enantiomer and the carbon attached directly to that carbon (the one not in a ring) is an R enantiomer.
I decided to treat the benzene rings as substituents (phenyl groups). Thus, the longest carbon skeleton has three carbons. The carbon attached to the nitrogen is the number 1 carbon.
I came up with the following name:
(1S,2R)-1,2-diphenyl-1-propanamine
Would you agree? Thanks.
