- #1
Mr Davis 97
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- 44
So we have ##x^3=1##. I have a really simple question. Why isn't it true that ##x^3 = 1## if and only if ##x = 1##, when we consider that if we take cube root of both sides and we can then take the cube again? Of course there are two other complex roots, but what am I missing in my naive logical argument?