Need help with lots of different types of problems

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SUMMARY

This discussion focuses on solving two mathematical problems involving algebra and geometry. The first problem requires calculating the new dimensions of a chocolate bar after reducing its volume by 20%, while maintaining its thickness. The original dimensions are 12 cm in length, 7 cm in width, and 3 cm in thickness, leading to a new volume of 201.6 cm³. The second problem involves finding the value of k in the quadratic equation x² - kx + 4 = 0, specifically when it has a repeated real solution, which is determined by ensuring the discriminant (b² - 4ac) equals zero.

PREREQUISITES
  • Understanding of volume calculation (lwh) for rectangular prisms.
  • Knowledge of quadratic equations and their properties.
  • Familiarity with the concept of discriminants in algebra.
  • Ability to solve equations using the quadratic formula.
NEXT STEPS
  • Learn how to apply the quadratic formula to solve equations.
  • Study the properties of quadratic equations, focusing on repeated real solutions.
  • Explore volume reduction techniques in geometric problems.
  • Practice solving algebraic equations involving multiple variables.
USEFUL FOR

Students studying algebra, educators teaching mathematical concepts, and anyone interested in solving geometric and algebraic problems efficiently.

  • #31
there is no where to put pharentheses on the windows calc
 
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  • #32
yes that's right, now plug both of the numbers into the 12-x, 7-x and if you get a negative number then that's not the solution you need
 
  • #33
ok! yay I almost got it. lol I can't believe you have spent so much time online helping me with something so tedious! I appreciate it so much though...now let's see if I can get it this time...
 
  • #34
hehe no problem I am just watching television
 
  • #35
ok so l=11.07 and w=6.07 :) When rounded
 
  • #36
RubyRed said:
ok so for the first one I got 18.07029 so on and so on and for the second one I got
0.929702 so on and so on...is that right?

if you got that then how could you get 11.7 and 6.7?
 
  • #37
when I take the l=12-.93 which means that l= 11.07 and the width would be 7-.93 which is the 6.7
I could already tell the 18.07 wouldn't work because it would be a negative number when subtracted from the 12 and 7.
 
  • #38
ooooo hehe sorry thought you meant 11.7 not 11.07 >.< but yea that's the answer :) hehe took a while to solve it
 
  • #39
GOSH it took FOREVER! But I got it! yay! haha thanks so much for your help, I am sure I will be on this forum often, so maybe I will put you through math hell and help me again sometime. lol But for now I have had ENOUGH math, ugh, thanks again. Talk to you later! G'Night
 
  • #40
hehe no problem, glad i could help
 

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