Newton's Interpolation, numerical methods question

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Discussion Overview

The discussion centers around the First Order of Newton's Interpolation and its comparison with Lagrange's Interpolation. Participants are seeking clarification on the equations and methodologies involved in these numerical methods.

Discussion Character

  • Technical explanation
  • Debate/contested

Main Points Raised

  • One participant asks for the equation for the First Order of Newton’s Interpolation, referencing Lagrange’s Interpolation as a known method.
  • Another participant describes a method for finding the nth term involving derivatives, but does not provide a clear formula.
  • A different participant challenges the clarity of the nth term calculation, stating that the only known formula is "Newton's divided difference" which does not involve derivatives.
  • This participant also provides a linear interpolation formula that aligns with the values given by Lagrange's formula, suggesting that all linear interpolation schemes between two points yield the same results.
  • A later reply from the same participant acknowledges a typographical error in their previous message regarding the nth term calculation.

Areas of Agreement / Disagreement

Participants express differing views on the formulation of Newton's Interpolation, with some confusion regarding the use of derivatives and the relationship to Lagrange's method. No consensus is reached on the correct formulation or approach.

Contextual Notes

There are limitations in the clarity of the equations presented, and assumptions about the familiarity with mathematical notation may affect understanding. The discussion also reflects varying interpretations of the term "first order" in the context of interpolation.

albema
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Can anyone tell me what is the equation for First Order of Newton’s Interpolation?

The one of Interpolation I know is Lagrange’s Interpolation such as

[tex]p(x)= \frac {x-x1}{x0-x1} f(x0) + \frac {x-x0}{x1-x0} f(x1)[/tex]

and so on ...

Thanks in advance
 
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well, i don't have math type on this computer, so you will have to bear with me, but:

the nth term is found by dividing the function evaluated at the n-1th term by the derivative of the function evaluated at the n-1th term and then subtracting that from the nth term.

that's it!
 
How can you find the nth term by subtracting something from the nth term?

The only Newton Interpolation formula I know is "Newton's divided difference" formula- which does not involve finding derivatives. It's a bit complicated to write out but here is a good explanation from Wolfram:
http://mathworld.wolfram.com/NewtonsForwardDifferenceFormula.html.

As far as "first order" is concerned, it is just f(x)= f(x0)+ (f(x1)- f(x0))(x- x0)/(x1-x0). Which obviously takes on the correct values at x= 0 and x= 1 and linearly interpolates between. If you look closely you will see that it gives exactly the same values as Lagrange's formula: all linear interpolation schemes between two points are the same.
 
wunderboy said:
well, i don't have math type on this computer, so you will have to bear with me, but:

the nth term is found by dividing the function evaluated at the n-1th term by the derivative of the function evaluated at the n-1th term and then subtracting that from the nth term.

that's it!

good point... should be subtracted from the n-1th term. bad typing on my part! thanks for noticing;-)
 

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