Number of Divisors: 10 Divisors of 21600 Divisible by 10

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Discussion Overview

The discussion revolves around determining how many divisors of the number 21600 are divisible by 10 but not by 15. Participants explore the prime factorization of 21600 and the conditions for divisibility related to the factors of 10 and 15.

Discussion Character

  • Exploratory
  • Mathematical reasoning

Main Points Raised

  • One participant asks how many divisors of 21600 are divisible by 10 but not by 15.
  • Another participant requests clarification on the initial thought process or attempts made by the original poster.
  • A participant provides the prime factorization of 21600 as \(2^5 \times 3^3 \times 5^2\) and discusses the conditions for a number to be divisible by 10 and not by 15.
  • Further, a participant suggests expressing 21600 in a different form to facilitate the analysis of its divisors and encourages considering the parameters of the divisor while applying the fundamental counting principle.

Areas of Agreement / Disagreement

Participants generally agree on the importance of prime factorization and the conditions for divisibility, but the discussion remains unresolved regarding the exact number of divisors that meet the specified criteria.

Contextual Notes

Participants have not yet reached a consensus on the method to count the divisors, and there are unresolved steps in applying the fundamental counting principle to the problem.

juantheron
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How many divisors of $21600$ are divisible by $10$ but not by $15$?
 
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In order to assist our helpers in knowing just where you are stuck, can you show what you have tried or what your thoughts are on how to begin?
 
Prime factor of $21600 = 2^5 \times 3^3 \times 5^2$

Now No. is Divisible by $10$ If It Contain at least one factor of $5$ and $2$

and No. is Non Divisible If It not Contain at least one $3$ and $5$

Now How Can I proceed after that

Thanks
 
I think you are on the right track with the prime factorization. I would write it as:

$$21600=2\cdot5\left(2^4\cdot3^3\cdot5 \right)= 10\cdot2^4\cdot3^3\cdot5$$

Now looking at the factor to the right of 10, consider a divisor of 21600 of the form:

$$2^{n_1}\cdot3^{n_2}\cdot5^{n_3}$$

What are the number of choices we have for the parameters $n_i$ such that this factor is not divisible by 3? Then apply the fundamental counting principle. What do you find?
 

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