Number of HCl Equivalents in 100mL of pH 4 Solution

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To determine the number of equivalents of HCl in a 100 mL solution with a pH of 4, the concentration of H+ ions is calculated to be 10^-4 M. This corresponds to 10^-5 moles of HCl in the solution, as HCl is assumed to ionize completely. The discussion clarifies that while HCl can react with a base, the calculation of equivalents focuses on the available H+ ions rather than the specifics of the reaction with water. It is emphasized that for strong acids like HCl, complete dissociation is a key factor in determining concentration. Overall, the calculation of equivalents is straightforward when considering complete ionization.
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Homework Statement



Number of equivalents of HCL present in 100 ml of it's solution whose PH is 4

Homework Equations



PH= -Log[H+][/B]

The Attempt at a Solution



I used the above equation to find the concenteration of H+ and found it to be 10^-4 M.I am stuck after that. I searched the wiki and found a equivalent to be a substance which releases 1 mol of H+ in acid-base reaction but I don't find an acid base reaction here?[/B]
 
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You need the volume of the solution in liters. If you know the molarity, (and yes, you calculated it correctly), how do you compute the number of moles? ## \\ ## HCl is assumed to ionize completely in solution. Likewise when mixed with a base, the HCl is assumed to react with 100% efficiency.
 
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Number of moles of HCl in the solution is then 10^-5 moles.

Do I have to assume to consider HCL as acid and water as base and proceed with this reaction

HCL(aq)-------->H+(aq)+Cl-(aq)
 
Hydrous Caperilla said:
Number of moles of HCl in the solution is then 10^-5 moles.

Do I have to assume to consider HCL as acid and water as base and proceed with this reaction

HCL(aq)-------->H+(aq)+Cl-(aq)
Not necessary, and that would really be incorrect (to assume it is reacting with water). What you are computing is the number of moles of ## H^+ ##, also called "equivalents" that are available to react with a basic (meaning "base") solution, such as NaOH. ##\\ ## And you computed it correctly. ## \\ ## (Such a reaction would neutralize the NaOH with the result being a NaCl (salt) solution which is neutral (neither acidic or basic). The ## OH^- ## would react with ## H ^+ ## to form ## H_2 O ## which is of course water).
 
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So regardless of the base,HCL will ionise completely and so we can calculate H+ ...right?
 
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Hydrous Caperilla said:
So regardless of the base,HCL will ionise completely and so we can calculate H+ ...right?
That is correct.
 
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Thanx for the help
 
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Hydrous Caperilla said:
So regardless of the base,HCL will ionise completely and so we can calculate H+ ...right?

When calculating number of equivalents dissociation is irrelevant in general. For a weak acid - like acetic - number of equivalents means "amount of H+ that can react" - not necessarily "dissociated".

In the case of your question 100% dissociation was an important factor in determining HCl concentration, other than that it didn't matter.
 
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A fair point
 

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