Numerical method to solve a fourth order ODE

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SUMMARY

The discussion focuses on solving the fourth-order ordinary differential equation (ODE) represented as K*w'''' + c*w = q. The user seeks a numerical solution method, having already utilized DSolve in Matlab for symbolic solutions. A suggested approach involves transforming the ODE into its characteristic polynomial form, (KD4 + C)w = 0, and factoring it to derive individual solutions from (D + a)w = 0. This method allows for the construction of general solutions through linear combinations of the derived solutions.

PREREQUISITES
  • Understanding of ordinary differential equations (ODEs)
  • Familiarity with Matlab and its DSolve function
  • Knowledge of characteristic polynomials
  • Basic skills in numerical methods for solving differential equations
NEXT STEPS
  • Explore numerical methods for solving ODEs, such as the Runge-Kutta method
  • Learn about Matlab's numerical solvers, specifically ode45 and ode23
  • Investigate the method of finite differences for approximating solutions to ODEs
  • Study the theory behind linear combinations of solutions for higher-order ODEs
USEFUL FOR

Mathematicians, engineers, and students involved in numerical analysis or differential equations, particularly those seeking to solve higher-order ODEs numerically.

rsluijs
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I've got the following ODE:

K*w''''+c*w = q

I can solve this with DSolve (from Matlab), but how can I solve this in a numerical way?

Thanks!
 
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Welcome to PF!

rsluijs said:
I've got the following ODE:

K*w''''+c*w = q

I can solve this with DSolve (from Matlab), but how can I solve this in a numerical way?

Thanks!

Hi rsluijs! Welcome to PF! :smile:

To solve K*w''''+c*w = 0, you can replace ' by the operator D, giving the "characteristic polynomial" (KD4 + C)w = 0,

and you factor that to (D + a)(D + b)(D + c)(D + d)w = 0,

and then solve each individual (D + a)w = 0 etc, and add linear combinations of those solutions. :wink:
 

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