Ok ty (can u checked this one)

[ArmiAldi]

let me know is this correct or no?
dx)/(x lnx^4)
(dx)/(x 4lnx)
(dx)/(4x lnx)
u = lnx
du/dx = 1/x
(du)(x) = dx

lnx = u dx = (du)(x)

(du)(x)/(4x u)
du/4u
(1/4)ln(u)


(1/4)ln(lnx)

 

[cristo]

I am moving this question to the homework forums. Please post all homework/coursework questions there in future!

 

[HallsofIvy]

let me know is this correct or no?
dx)/(x lnx^4)

You mean the integral of this don't you?

(dx)/(x 4lnx)
(dx)/(4x lnx)
u = lnx
du/dx = 1/x
(du)(x) = dx

lnx = u dx = (du)(x)

(du)(x)/(4x u)
du/4u
(1/4)ln(u)


(1/4)ln(lnx)

Well, (1/4) ln(ln(x))+ C. And you didn't really need to write "(du)(x)/(4x u)". From du/dx= 1/x, du= dx/x and you can go ahead and substitute du for the dx/x you already have in the integral.