On Bessel function's orthogonality

  • Context: Graduate 
  • Thread starter Thread starter samuelandjw
  • Start date Start date
  • Tags Tags
    Bessel Orthogonality
samuelandjw
Messages
22
Reaction score
0
Use the orthogonality relation of Bessel function to argue whether the following two integrals are zero or not:
[itex]\displaystyle\int_0^1J_1(x)xJ_2(x)dx[/itex]
[itex]\displaystyle\int_0^1J_1(k_1x)J_1(k_2x)dx[/itex], where [tex]k_1,k_2[/tex] are two distinct zeros of Bessel function of order 1.

The textbook we are using is Boas's Mathematical Methods in the Physical Sciences, so the formulas that are available to us are a set of recursion relations of Bessel function, and the orthogonality relations between Bessel function of the same order: http://upload.wikimedia.org/math/c/d/b/cdb1e8ba98f7855eba9777024cce03fd.png.

For the first integral, the two Bessel functions are of different order, and there is no zeros in the arguments of the two functions, so I have no idea how to link the first integral to the orthogonality relation of Bessel functions.

For the second integral, my argument is that since [itex]\displaystyle\int_0^1J_1(k_1x)xJ_1(k_2x)dx[/itex] is zero, the 2nd integral (note that there is no x between the two Bessel function) cannot be zero. I think this argument is quite weak. Would anyone give me a better argument?

Thanks.
 
on Phys.org
The first one integral(positive function)=positive number
 
Last edited:
lurflurf said:
The first one integral(positive function)=positive number

Thanks for your reply. We can surely say that [tex]J_1(x),J_2(x)[/tex] are positive functions between x=0 and x=1 because the first nontrivial zeros are larger than 1. One has to somehow use the information of the location of zeros to reach this conclusion. Suppose we don't have this information, is it still possible to argue that the integral is non-zero?
 

Similar threads

  • · Replies 5 ·
Replies
5
Views
2K
Replies
1
Views
11K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 6 ·
Replies
6
Views
4K
  • · Replies 1 ·
Replies
1
Views
1K
Replies
1
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 13 ·
Replies
13
Views
4K