Partial Derivatives: Solve f(x,y)=1,000+4x-5y

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Homework Help Overview

The discussion revolves around finding the second partial derivatives of the function f(x, y) = 1,000 + 4x - 5y. Participants are exploring the concepts of partial derivatives and their calculations.

Discussion Character

  • Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the calculation of the first second partial derivative, noting that the result is 0. Questions arise regarding the method used to arrive at this result and the interpretation of mixed partial derivatives.

Discussion Status

Some participants have provided guidance on how to approach the problem and suggested reviewing textbook materials for additional explanations. There is an ongoing exploration of the meaning and calculation of the various second partial derivatives, with no explicit consensus reached.

Contextual Notes

Participants mention that the original poster feels the topic has not been adequately covered in class, indicating a potential gap in understanding the material. There is also a suggestion to utilize LaTeX for clearer representation of mathematical expressions.

Julian12345
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Homework Statement


Find
∂2f
∂x2
,
∂2f
∂y2
,
∂2f
∂x∂y
, and
∂2f
∂y∂x
.
f(x, y) = 1,000 + 4x − 5y

Homework Equations

The Attempt at a Solution


Made somewhat of an attempt at the first one and got 0, however my teacher has poorly covered this in class, and I would value some further explanation.
 
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0 is correct for the first one, but how did you get it? Set out your working and you may be able to see how to do the others using a similar approach. If not, somebody may be able to help you move on from where you are up to.

What is your understanding of the meaning of ##\frac{\partial^2f}{\partial x\partial y}##?

By the way, to write partial derivatives neatly, use latex code. The following code
\frac{\partial^2f}{\partial x^2}
when enclosed between double-# delimiters at each end, gives ##\frac{\partial^2f}{\partial x^2}##.
 
andrewkirk said:
0 is correct for the first one, but how did you get it? Set out your working and you may be able to see how to do the others using a similar approach. If not, somebody may be able to help you move on from where you are up to.

What is your understanding of the meaning of ##\frac{\partial^2f}{\partial x\partial y}##?

By the way, to write partial derivatives neatly, use latex code. The following code
\frac{\partial^2f}{\partial x^2}
when enclosed between double-# delimiters at each end, gives ##\frac{\partial^2f}{\partial x^2}##.

Alternatively, you can just write ##\partial^2 f/ \partial x^2##, and it should still be perfectly readable. Right-click on the displayed expression and then choose the "display math as Tex commands" menu item.
 
Julian12345 said:

The Attempt at a Solution


Made somewhat of an attempt at the first one and got 0, however my teacher has poorly covered this in class, and I would value some further explanation.
In addition to what your teacher has covered in class, there should be some explanation in your textbook. Have you read the section that discusses partial derivatives? There should be some examples in your book. You shouldn't rely only on what the teacher does in class.
 
If you consider multiple derivatives as a sequence, these problems become less confusing.
##\frac{\partial ^2 f}{\partial x^2 } = \frac{\partial }{\partial x }\left( \frac{\partial }{\partial x}f\right)##
Similarly,
##\frac{\partial ^2 f}{\partial x \partial y } = \frac{\partial }{\partial x }\left( \frac{\partial }{\partial y}f\right)##.
Do the operations in order, and you will get the correct result.
 

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