B Peculiar View of Density Matrices: Is There a Problem?

  • B
  • Thread starter Thread starter Heidi
  • Start date Start date
  • Tags Tags
    Density Matrices
Click For Summary
The discussion centers on the interpretation of density matrices, with one participant expressing a non-statistical view similar to Hilbert vectors. They question whether this perspective is problematic, particularly regarding the representation of mixtures of pure states. Another contributor clarifies that density matrices serve as statistical operators that can describe quantum states, emphasizing their mathematical properties. The conversation highlights the dual nature of density matrices in quantum mechanics, where they can represent both pure and mixed states. Ultimately, the need for a comprehensive understanding of density matrices in various contexts is underscored.
Heidi
Messages
420
Reaction score
40
Hi Pfs , happy new year.
I wonder if there is a problem with the manner i see density matrices:
I use to consider them without a statistical point of view , just like i do with Hilbert vectors. no more no less. So the points on the Block sphere are only pecular points of those which are inside.
Of course if they can also describe mixtures of pure states in a statistical point of view.
is there a problem with that point of view?
 
Physics news on Phys.org
As for the titled question, I think yes because I have no idea for information to add to density matrix.
 
Heidi said:
Hi Pfs , happy new year.
I wonder if there is a problem with the manner i see density matrices:
I use to consider them without a statistical point of view , just like i do with Hilbert vectors. no more no less. So the points on the Block sphere are only pecular points of those which are inside.
Of course if they can also describe mixtures of pure states in a statistical point of view.
is there a problem with that point of view?
Could you give an example? Density matrices are used in more than one context, some of which might be more complete than others.
 
The quantum state of an arbitrary system is described by the statistical operator ##\hat{\rho}##, which is a positive semidefinite self-adjoint operator with trace 1. It's a pure state, if it can be written as ##\hat{\rho}=|\psi \rangle \langle \psi|## with some normalized vector ##|\psi \rangle##, i.e., iff ##\hat{\rho}^2=\hat{\rho}##.
 
  • Like
Likes physicsworks
For the quantum state ##|l,m\rangle= |2,0\rangle## the z-component of angular momentum is zero and ##|L^2|=6 \hbar^2##. According to uncertainty it is impossible to determine the values of ##L_x, L_y, L_z## simultaneously. However, we know that ##L_x## and ## L_y##, like ##L_z##, get the values ##(-2,-1,0,1,2) \hbar##. In other words, for the state ##|2,0\rangle## we have ##\vec{L}=(L_x, L_y,0)## with ##L_x## and ## L_y## one of the values ##(-2,-1,0,1,2) \hbar##. But none of these...

Similar threads