Percentages on Variables: Find the number of students who took this exam

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SUMMARY

The discussion centers on calculating the total number of students who appeared for an exam based on their performance across five topics. The breakdown includes 10% passing all topics, 10% failing all, 20% passing one topic, 25% passing two topics, 24% passing four topics, and 500 students passing exactly three topics. The correct total number of students is determined to be 2500, as the calculations based on the remaining percentages of students were misapplied initially, leading to an incorrect estimate of 2016.

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Merotzu
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Thread moved from the technical forums to the schoolwork forums
TL;DR Summary: i want to understand the concept.
i denote the students as X,
0.1X students passed all topics
0.1X students did not pass any topics
0.80X remaining students
0.2*0.80X students passed in one topic
0.25*0.80X students passed in 2 topics only
0.24*0.80X students passed in 4 topics only
so going by this pattern
out of the 100 percent of remaining students
(100-20-25-24)*0.80X=500 as 20% of the overall students are students who passed all topics or no topics.But i am not getting the answer

In a practice paper at 2iim.com, questions were given from 5 topics. Out of the appearing students, 10% passed in all topics while 10% did not pass in any. Of the remaining, 20% passed in one topic only and 25% in two topics only. If 24% of the total students passed 4 topics only and 500 students passed in 3 topics only, find the total number of students who appeared in the examination?
 
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Please show us your work on this question. We are not allowed to provide tutorial assistance until you show your work. Thank you.
 
below is the attached problem file
 

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could you take a moment and tell me what is the logical mistake in the solution of my problem
 
Merotzu said:
Out of the appearing students, 10% passed in all topics while 10% did not pass in any. Of the remaining, 20% passed in one topic only and 25% in two topics only. If 24% of the total students passed 4 topics only and 500 students passed in 3 topics only, find the total number of students who appeared in the examination?
Sorry if you saw my initial feedback on the problem before I deleted it. The question is pretty confusing the way they are stating it, but here is my attempt to start it (so we can compare my work to yours):
Code:
Problems	Pass
--------	------------
5		     10%
4		     24%
3		     500 total
2		     25% * 80%
1		     20% * 80%		
0		     10%

So adding up the percentages will give you the percentage left that equals the 500. What percentage did you get for that group?
 
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i got 2016 approximately.But the correct answer is 2500
 
berkeman said:
So adding up the percentages will give you the percentage left that equals the 500. What percentage did you get for that group?

Merotzu said:
i got 2016 approximately
That's not what he asked. First, you need to know what percent of the total the 500 is.
 
i think it is 31 percent of the remaining 80 percent of the students.But i am getting the wrong answer by doing in this method
 
Merotzu said:
But the correct answer is 2500
Yes, that is what I get using my table above. :smile:
 
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Merotzu said:
i think it is 31 percent of the remaining 80 percent of the students.But i am getting the wrong answer by doing in this method
That is wrong. Convert the percentages of the 80% into percentages of the total. Subtracting all the known percentages of the total, what do you get as the remaining percent of the total for the 500 who passed exactly 3 topics?
 

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