MHB Permutations of Comics, Novels, and Magazines Without Restrictions

[Bushy]

There are three separate bundles of reading material comprising of 4 comics, 2 novels and 3 magazines. They are placed together to form one pile.

In how many ways can this be done if there are no restrictions on where the individual items are to be placed?

I say 9! = 362880

Determine the number of permutations if the order of the comic books in each bundle does not change

I'm not sure what they mean by 'each bundle' here

 

[Jameson]

This question is worded really strangely.

If you're arranging these into one pile and the order of the comic books doesn't change then I would say it's [math]\frac{9!}{4!}[/math]. Dividing by $4!$ accounts for all the different ways you can order the comic books but keep everything else the same. Since we want just one order I would say this is the answer but again this question is worded in a way where I'm not sure.

 

[Bushy]

This question is worded really strangely.

I agree, the answer given is 1782, I've been trialing different answers to arrive there with no luck.