Perturbation Theory (Non-Degenerate)

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SUMMARY

The discussion focuses on applying first-order perturbation theory to calculate the energy of the quantum ground state for a perturbed Hamiltonian, specifically for a system described by the potential V(x) = (1/2)mω²x²(1 + x²/L²). The Hamiltonian is expressed as H = H₀ + Hₚ, where H₀ is the unperturbed Hamiltonian of the harmonic oscillator, H₀ = ℏω(n + 1/2), and Hₚ = (1/2L²)mω²x⁴ represents the perturbation. The ground state wave function of the unperturbed oscillator is essential for evaluating the energy correction using the integral = ∫ψ₀*(Hₚ)ψ₀.

PREREQUISITES
  • Understanding of quantum mechanics and Hamiltonian operators
  • Familiarity with perturbation theory, specifically first-order perturbation theory
  • Knowledge of harmonic oscillator wave functions and their properties
  • Basic calculus for evaluating integrals in quantum mechanics
NEXT STEPS
  • Study the derivation of the harmonic oscillator wave functions
  • Learn about first-order perturbation theory applications in quantum mechanics
  • Explore the concept of anharmonic oscillators and their energy corrections
  • Practice calculating energy corrections using perturbation theory with various potentials
USEFUL FOR

Students and researchers in quantum mechanics, particularly those studying perturbation theory and its applications to quantum systems, including physicists and advanced undergraduate students in physics programs.

jhosamelly
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If I have V(x)=\frac{1}{2}m\omega^{2}x^{2} (1+ \frac{x^{2}}{L^{2}})

How do I start to solve for the hamiltonian Ho, the ground state wave function ?? Calculate for the energy of the quantum ground state using first order perturbation theory?
 
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H= H_{0} + H_{p}

So basically, you have an aditional term, H_{p} = \frac{1}{2L^{2}}mω^2 x^4, that perturbates your hamiltonian.
You already know the solution for the harmonic oscillator, H= H_{0} = \hbarω(n + \frac{1}{2}), so you just have to find the corrections for the H_{p}.

hope i made myself clear ( ;
 
so does this mean my hamiltonian would be H= \hbarω(n + \frac{1}{2}) + \frac{1}{2L^{2}}mω^2 x^4 ?
 
Don't you know the ground state wave function of unperturbed oscillator.you can see them elsewhere and then just evaluate(with normalized eigenfunctions)
<E>=∫ψ0*(Hp0
 
I actually don't know the wave function.. That's also my prob... if i only know the wave function I'll be able to solve this.
 
Last edited:
Is this the same for an anharmonic oscillator? That is the problem about.
 
No,you use unpertubed harmonic oscillator wave function for calculation.
 

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