1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

PH after titration of Weak Acid with a Strong Base

  1. Mar 25, 2008 #1
    1. The problem statement, all variables and given/known data
    Titrating .1006M CH3COOH with .2012M NaOH. pKa=4.74, Ka=1.8*10^-5
    What is the pH at the equivalence point of the titration?


    2. Relevant equations
    pKa = -log(Ka) pH = -log[H+]


    3. The attempt at a solution

    Alright, after setting up an ICE table (in order to find [H+] at the equivalence point) I realized that when you work it out Ka = [H+], however when I plugged that in I got a pH in th 4-5 range when it should be above 7.
    Here is my Ka reasoning
    Ka = [A-][H+]/[HA]
    Ka = [Co+x][x]/[Co-x] Co = Initial Concentration
    x is very small (Weak acid, no/little disassociation)
    Ka = x
    Ka = [H+]


    Am I missing something or is my logic just wrong? Anything that could point me in the correct direction would be greatly appreciated.
     
  2. jcsd
  3. Mar 25, 2008 #2

    symbolipoint

    User Avatar
    Homework Helper
    Education Advisor
    Gold Member

    The pH at equivalence is the same as if you dissolved the sodium salt in water, without any acid or base. Now, you calculation should be based on just the effect of the sodium salt alone in the water.
     
  4. Nov 8, 2008 #3
    Late answer but i came across this question when i was looking for the same answer.

    Don't forget the answer your getting is pOH!
    Therefore pH = 14 - pOH (where your pOH will be between 5-6 for this type of question)
    pH = > 7
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?