- #1

yungman

- 5,726

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For example [tex]\Gamma[/tex](n+3/2+1)=[tex]\frac{(2n+3)(2n+1)!}{2^{2n+2}.n!}[/tex].

I cannot figure out how to write a series with:

n=0 => [tex]\Gamma[/tex](0-3/2+1)= -2[tex]\sqrt{\pi}[/tex]

n=1 => [tex]\Gamma[/tex](1-3/2+1)= [tex]\sqrt{\pi}[/tex]

n=2 => [tex]\Gamma[/tex](2-3/2+1)= 1/2[tex]\sqrt{\pi}[/tex]

n=3 => [tex]\Gamma[/tex](3-3/2+1)= 4/3[tex]\sqrt{\pi}[/tex]

This is not homework. I have spent 2 days on this and can't figure it out!

Thanks

Alan