# Please solve for x in this logarithmic equation? 4^x + 2^(x+1) = 60

4x + 2(x+1) = 60

N/A

## The Attempt at a Solution

4x + 2(x+1) = 60
22x + 2(x+1) = 60

I don't know where to go from there.

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Mentallic
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edit: ehild has the correct solution.

Last edited:
ehild
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## The Attempt at a Solution

4x + 2(x+1) = 60
22x + 2(x+1) = 60

I don't know where to go from there.

You are on the right track. Note that $2^{(x+1)}=2\cdot 2^x$ and $2^{2x}= (2^x)^2$. Then choose 2^x as new variable and solve the resultant second order equation.

ehild