Preparing 0.1M Nitric Acid (1000ml, 65% Nitric Acid)

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Discussion Overview

The discussion centers around the preparation of 1000ml of 0.1M Nitric acid using a 65% Nitric acid solution. Participants explore the calculations and steps necessary for dilution, including the use of specific gravity and molecular weight in their reasoning.

Discussion Character

  • Homework-related
  • Mathematical reasoning

Main Points Raised

  • One participant asks how to prepare the solution, providing the concentration and specific properties of the nitric acid.
  • Another participant reiterates the goal of making 1000ml of 0.1M Nitric acid and lists relevant properties such as specific gravity and molecular weight.
  • A third participant suggests using the formula provided to substitute the values for the calculation.
  • A fourth participant proposes starting with the number of moles of HNO3 needed and then calculating the grams of pure HNO3, noting the source is not pure but a 65% solution, indicating further steps are required.

Areas of Agreement / Disagreement

The discussion remains unresolved, with participants offering different approaches and calculations without reaching a consensus on the method to be used.

Contextual Notes

Participants reference specific equations and properties but do not clarify all assumptions or dependencies in their calculations, leaving some steps and definitions potentially ambiguous.

kaykay11
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how do I make 1000ml of 0.1M Nitric acid with 65% Nitric acide (specific gravity 1.42g) and Molecular weight 63g/mol
 
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Diluting acid with water

Homework Statement



To make 1000ml of 0.1M of Nitric acid with 65% Nitric acid.
Specific gravity= 1.42g/
Molecular weight= 63g/mol

Homework Equations


M = ((% x Specific gravity)/Molecular weight) x 10
cava = cfvf


The Attempt at a Solution

 


You presented a formula in your Relevant equations section. If you trust this formula then just substitute the values for the described information.
 
You could start with the number of moles of HNO3 you would want. If you know the moles of HNO3, then use formula weight to find number of grams of pure HNO3; but you know that your source is not pure, but instead is 65% w/w. so you have two more steps... can you derive them?
 

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