Proof by Induction: Showing AnAm = An+m

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SUMMARY

The discussion focuses on proving the matrix equation AnAm = An+m using mathematical induction. The matrix A is defined as A = [[1-n, -n], [n, 1+n]]. The proof involves establishing a base case for A_n A_0 = A_{0+n} and using an induction hypothesis for A_n A_m = A_{m+n}. Participants highlight that directly computing the product of A_m and A_n simplifies the proof process.

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  • Understanding of matrix multiplication
  • Familiarity with mathematical induction
  • Knowledge of 2x2 matrices
  • Basic linear algebra concepts
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Students in mathematics, particularly those studying linear algebra and proof techniques, as well as educators looking for examples of induction proofs involving matrices.

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Homework Statement



A= (1-n -n

n 1+n)

this is 2x2 matrix, sorry but i don't know which latex to use.


Show that AnAm = An+m

Homework Equations



n/a

The Attempt at a Solution



how do you proof by induction when there's 2 variable?
 
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1-n , -n



n , 1+n
 
annoymage said:
Show that AnAm = An+m

Homework Equations



n/a

The Attempt at a Solution



how do you proof by induction when there's 2 variable?

You do induction on one of the variables and leave the other with universal
quantifier

You take as base case: For all n A_n A_0 = A_{0+n}

and the induction hypthesis: For all n A_n A_m = A_{m+n}

and try to prove For all n A_n A_{m+1} = A_{m+1+n}
 
oooo, i see i see,
thank you very much. :)
 
It's actually easier to just compute the product of A_m and A_n
 
yeaaa, it is, why didn't i think of that. =.=

hoho thanks again
 

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