Proving 3 Divides at Least One Integer

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Homework Help Overview

The problem involves proving that for any integer n, at least one of the integers n, n + 2, or n + 4 is divisible by 3. The subject area pertains to number theory and divisibility.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the possible remainders when an integer is divided by 3 and consider the implications of these remainders for the integers in question. There is a suggestion to analyze cases based on the remainder.

Discussion Status

The discussion is ongoing, with some participants providing hints and others seeking clarification on how to formulate a proof. There is an emphasis on the need to show work and explore the implications of different cases.

Contextual Notes

Participants note the importance of adhering to forum rules regarding attempts at solutions, indicating that full solutions should not be provided directly.

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Homework Statement



Prove that 3 divides one of the integers n, n + 2, or n + 4, for any integer n.


Homework Equations





The Attempt at a Solution


 
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Try, ok? Any integer n has a remainder of either 0, 1 or 2 when divided by 3. Come on.
 
Okay...so what's the formula for proving that true is my question?

Thanks
 
Read the forum rules. You are supposed to put something in the "attempt at a solution section". I just gave you a hint. There really is no 'formula'.
 
Let n be any such integer. THen by the division algorithm there exist integers q and r such that

[tex]n=3q+r,[/tex]

[tex]n+2=3q_1+r[/tex]

[tex]n+4=3q_2+r[/tex] [tex]0\leq r<3[/tex]

i.e r=0, 1 or 2

Now, say if r=0, what happens? if r=1, what happens? if r=2 what happens?

P.S. This is what Dick said, i just wanted to make a little bit easier on you.
YOu MUST show your work next time.
 

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