MHB Proving ${\psi}_{n}(x)\le F(n)$ by Induction

  • Thread starter Thread starter sarrah1
  • Start date Start date
  • Tags Tags
    Induction
Click For Summary
SUMMARY

The discussion centers on proving the inequality ${\psi}_{n}(x) \le F(n)$ for $x \in [a, b]$ using mathematical induction. The user establishes the base case for $n=1$, confirming that ${\psi}_{1}(x) \le f(x,1) \le F(1)$. They successfully demonstrate that if ${\psi}_{n}(x) \le f(x,n)$ holds, then it follows that ${\psi}_{n+1}(x) \le F(n+1)$. This leads to the conclusion that the inductive step supports the original claim for all integers $n$.

PREREQUISITES
  • Understanding of mathematical induction
  • Familiarity with functions and inequalities
  • Knowledge of the definitions of ${\psi}_{n}(x)$ and $F(n)$
  • Basic comprehension of the interval notation $[a, b]$
NEXT STEPS
  • Research the properties of the function ${\psi}_{n}(x)$
  • Study the characteristics of the function $F(n)$
  • Explore advanced techniques in mathematical induction
  • Learn about the implications of inequalities in mathematical proofs
USEFUL FOR

Mathematicians, students studying mathematical proofs, and anyone interested in the application of induction in inequalities.

sarrah1
Messages
55
Reaction score
0
Hello

is my proof be correct ?

I wish to prove by induction that ${\psi}_{n}(x)\le F(n)$ , $x\in[a,b]$ ... (1)

Let there exists a function $f(x,n)$ such that if ${\psi}_{n}(x)\le f(x,n) $ then ${\psi}_{n}(x) \le F(n)$ .

I know that (1) is true for $n=1$ i.e. ${\psi}_{1}(x)\le f(x,1)\le F(1)$ ,

and I was able to prove that

${\psi}_{n+1}(x)\le F(n+1)$ , $x\in[a,b]$

would this implies ${\psi}_{n}(x)\le F(n)$

thanks
 
Physics news on Phys.org
sarrah said:
I wish to prove by induction that ${\psi}_{n}(x)\le F(n)$ , $x\in[a,b]$
Please provide the definitions of $\psi_n$, $F$, $a$ and $b$.
 

Similar threads

  • · Replies 6 ·
Replies
6
Views
1K
  • · Replies 3 ·
Replies
3
Views
971
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 15 ·
Replies
15
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K