Quadratic Equation: Finding Values of 'a' Between 2 and 4 with Only One Root

Join the discussion
Registration is free. Start your own thread to ask a follow-up.
4 replies · 4K views
Saitama
Messages
4,244
Reaction score
93

Homework Statement


Find all the values of 'a', so that exactly one root of the equation x2-2ax+a2-1=0, lies between the numbers 2 and 4, and no root is either equal to 2 or equal to 4.

Homework Equations


The Attempt at a Solution


Let f(x)=x2-2ax+a2-1
I tried to visualize the question by graph. The graph could have been like this (this is only a rough sketch):-
2qci6hi.jpg

From here, i get three inequalities,
f(2)<0 and f(4)>0 and D>0
Solving these inequalities, i get a can lie in interval (1,3).
But this is not the answer, the answer is (1,5)-{3}.
Then i thought that graph could be also like this:-
kb20d4.jpg

But this gives completely different set of inequalities, now i am completely stuck.

Any help is appreciated. :)
 
Physics news on Phys.org
Pranav-Arora said:

Homework Statement


Find all the values of 'a', so that exactly one root of the equation x2-2ax+a2-1=0, lies between the numbers 2 and 4, and no root is either equal to 2 or equal to 4.

Homework Equations


The Attempt at a Solution


Let f(x)=x2-2ax+a2-1
I tried to visualize the question by graph. The graph could have been like this (this is only a rough sketch):-
2qci6hi.jpg

From here, i get three inequalities,
f(2)<0 and f(4)>0 and D>0
Solving these inequalities, i get a can lie in interval (1,3).
But this is not the answer, the answer is (1,5)-{3}.
Then i thought that graph could be also like this:-
kb20d4.jpg

But this gives completely different set of inequalities, now i am completely stuck.

Any help is appreciated. :)

The quadratic formula simplifies the root to a function of "a", no need to use graphs, I think your right btw (1,5)-{3} is the union of (1,3) and (3,5)
 
Hey Pranav-Arora! :smile:

Pranav-Arora said:
I tried to visualize the question by graph. The graph could have been like this (this is only a rough sketch):-

Aha! You're drawing again. Good! :approve:

Solving these inequalities, i get a can lie in interval (1,3).

Yep.

Then i thought that graph could be also like this:-
But this gives completely different set of inequalities, now i am completely stuck.

Not stuck.
This is indeed another set of inequalities that you also have to solve.
The solution is the combination of both solutions.
 
hqjb said:
The quadratic formula simplifies the root to a function of "a", no need to use graphs, I think your right btw (1,5)-{3} is the union of (1,3) and (3,5)

Oh yes, i knew about it, it will reduce to (x-a)2-1=0 and then we can proceed on the next steps. Thanks for the reply! :)

Hello ILS! :smile:

The one who always helps me said:
Aha! You're drawing again. Good! :approve:
Thanks. :blushing:

I Like Serena said:
Not stuck.
This is indeed another set of inequalities that you also have to solve.
The solution is the combination of both solutions.
Now i understand it. Thanks once again! :smile: