Question about commuting operators

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The discussion centers on the definition and calculation of the commutator of vector operators, specifically [Jk, Ll] = iħΣmεklmLm. Participants clarify that to compute [J, L], one must first establish a multiplication method for vectors, with the tensor product being the most straightforward approach. The commutator is defined as [A, B] = AB - BA, leading to the tensor representation T_{ij} = A_i B_j. The resulting commutator [A, B] is expressed as T'_{ij} = T_{ij} - T_{ji}.

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Frank Einstein
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Hi everybody. I have a (I gess rather silly) question.

If I define [Jk,Ll]=iħΣmεklmLm, what would happen if I made [J, L]?. I gess it would be iħΣjεiijLi=0.

Can someone please confirm this?

Thanks for reading.
 
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If ##\mathbf J## and ##\mathbf L## are both vector operators, how are we supposed to define ##\mathbf J \mathbf L## and ##\mathbf L \mathbf J##?
 
Frank Einstein said:
Hi everybody. I have a (I gess rather silly) question.

If I define [Jk,Ll]=iħΣmεklmLm, what would happen if I made [J, L]?. I gess it would be iħΣjεiijLi=0.

Can someone please confirm this?

Thanks for reading.
By [itex][\boldsymbol{J}, \boldsymbol{L}[/itex], do you mean the commutator of the vectors? The definition of commutator is this:
[itex][A,B] = AB - BA[/itex], so to make sense of a commutator, you must first have a notion of multiplication. What notion of multiplication of vectors do you mean?

I think the most straight-forward is the tensor product. If you have two vectors [itex]\boldsymbol{A}[/itex] and [itex]\boldsymbol{B}[/itex], then you can define [itex]\boldsymbol{A}\boldsymbol{B}[/itex] to the be the tensor [itex]\boldsymbol{T}[/itex] with 9 components:

[itex]T_{ij} = A_i B_j[/itex]

where [itex]i[/itex] and [itex]j[/itex] range from 1 to 3. In that case, the commutator [itex][\boldsymbol{A},\boldsymbol{B}][/itex] would be just the tensor [itex]\boldsymbol{T}'[/itex] with components [itex]T'_{ij} = T_{ij} - T_{ji}[/itex]
 

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